Q. In this reaction, $CH_{3}CHO + HCN \longrightarrow CH_{3}CH(OH)CN\$ $\overset{\ \ \ \ \ H.OH\ \ \ \ \ \ }{\rightarrow}\ CH_{3}CH(OH)COOH$ an asymmetric centre is generated. The acid obtained would be
A) 50%D+50%L-isomer
B) 20%D+80%L-isomer
C) D-isomer
D) L-isomer
Explanation
(a)
Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exists as $d$ and $l$ forms whose ratio 1:1.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.