(b)
[image:12_image388.emf]
Due to [image:12_image389.emf] $(e^{-}withdrawing\ tendency)$ carbocation will appear farther to that (terminal).
Hence, product is $R_{3}N - CH_{2} - CH_{2}Br.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.