An organic compound having molecular mass 60 is found to contain C=20%, H=6.67% and N=46.67% while rest is oxygen. On heating it gives $NH_{3}$ along with a solid residue. The solid residue gives violet colour with alkaline copper sulphate solution. The compound is

Question

Dr. Abubacker · Accepted Answer

(b)
[table] Element | Percentage | $\frac{Percentage}{at.wt.}$ | Simple ratio ; C | 20.0 | $\frac{20.0}{12} = 1.66$ | $\frac{1.66}{1.66} = 1$ ; H | 6.67 | $\frac{6.67}{1} = 6.67$ | $\frac{6.67}{1.66} = 4$ ; N | 46.67 | $\frac{46.67}{14} = 3.33$ | $\frac{3.33}{1.66} = 2$ ; O | 26.66 | $\frac{26.66}{16} = 1.66$ | $\frac{1.66}{1.66} = 1$ [/table]
Empirical formula$= CH_{4}N_{2}O$
Empirical formula weight
$\ \ \ \ \ \ \ \  = 12 + (4 	imes 1) + (2 	imes 14) + 16 = 60$
$	herefore\ \ n = \frac{mol.formula\ weight}{emp.formula\ weight}$
$\ \ \ \ \ \ \ \ \  = \frac{60}{60} = 1$
$	herefore$ Molecular formula=$CH_{4}N_{2}O$
Given compound gives biuret test.Thus, given compound is urea $\left( NH_{2} ight)_{2}CO.$

Q. An organic compound having molecular mass 60 is found to contain C=20%, H=6.67% and N=46.67% while rest is oxygen. On heating it gives $NH_{3}$ along with a solid residue. The solid residue gives violet colour with alkaline copper sulphate solution. The compound is

Explanation

Reviewed by Dr. Abubacker

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