Q. In Carius method of 0.099 g orgainc compound gave 0.287 g $AgCl$. The percentage of chlorine in the compound will be
A) 28.6
B) 71.7
C) 35.4
D) 64.2
Explanation
(b)
% of chlorine $= \frac{35.5}{143.5} \times \frac{mass\ of\ AgCl}{mass\ of\ the\ compound\ } \times 100$
$= \frac{35.5}{143.5} \times \frac{0.287}{0.099} \times 100$
$= 71.71\ \%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.