(d)
Empirical formula of acid $= CH_{2}O_{2}$
We know that molecular formula $= n$ (empirical formula)
If $n = 1$ molecular formula $= \left( CH_{2}O_{2} \right)_{1} = CH_{2}O_{2}$
If $n = 2$ molecular formula $= \left( CH_{2}O_{2} \right)_{2} = C_{2}H_{4}O_{4}$
If $n = 3$ molecular formula $= \left( CH_{2}O_{2} \right)_{3} = C_{3}H_{6}O_{6}$
Thus, the probable molecular formula $= CH_{2}O_{2}$