Explanation

(c)
Isomers of $C_{4}H_{10}O$ are as follows
(i) $H_{3}C - CH_{2} - CH_{2} - CH_{2} - OH$
butanol-1
(ii) $H_{3}C - CH - CH_{2} - CH_{3}$
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OH
butanol-2
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
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(iii) $CH_{3} - CH - CH_{2} - OH$
2-methyl propanol -1
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}\$
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(iv) $H_{3}C - C - OH$
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$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ CH_{3}$
2-methyl propan -2-ol
(v) $H_{3}C - CH_{2} - O - CH_{2} - CH_{3}$
Diethyl ether
[image:12_image446.emf]
Hence, three isomeric ethers are possible.