Q. Correct order of stability is
A) $HC \equiv \overline{C} > CH_{2} = \overline{C}H > CH_{3} - \overline{C}H_{2}$
B) ${CH}_{3} - \overline{C}H_{2} > CH_{2} = \overline{C}H > CH_{\ } \equiv \overline{C}$
C) ${CH}_{3} - \overline{C}H_{2} > CH_{\ } \equiv CH \cong CH_{2} = \overline{C}H_{\ }$
D) All are equally stable
Explanation
(a)
Stability of alkyl carbanion $\propto \underset{magnitude\ of\ negative\ charge}{\overset{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }{\rightarrow}}\$and magnitude of negative charge $\propto + I$ power of the group. Hence, acetylenic carbanion is more stable than vinylic carbanion which is more stable than alkyl carbanion
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.