Q. Geometry of methyl free radical is
A) Pyramidal
B) Planar
C) Tetrahedral
D) Linear
Explanation
(b)
Number of hybrid orbitals =number of $\sigma$-bonds+number of $lps$
[image:12_image487.emf]
∴Number of hybrid orbitals =3+0=3
Hence, hybridisation is $sp^{2}$ and geometry is planar.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.