Q. Which of the following will exhibit $cis - trans$ isomerism?

A) $CH_{2}Br - CH_{2}Br$
B) $CBr_{3} - CH_{3}$
C) $CHBr = CHBr$
D) $CBr_{2} = CH_{2}$
Explanation

(c)
Due to restricted rotation about double bond, the alkene shows geometrical isomerism because the relative position of atoms or groups attached to the carbon atoms of the double bond get fixed. If same groups or atoms attached with double bond bearing carbon, then alkene doesn’t show geometrical isomerism.
[image:12_image496.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.