Q. Which of the following orders is correct regarding the acidity of carboxylic group?
A) $CH_{3}CH_{2}CH(Cl)COOH > CH_{3}CH(Cl)CH_{2}COOH > ClCH_{2}CH_{2}CH_{2}COOH$
B) $CH_{3}CH_{2}CH(Cl)COOH < CH_{3}CH(Cl)CH_{2}COOH < ClCH_{2}CH_{2}CH_{2}COOH$
C) $CH_{3}CH_{2}CH(Cl)COOH > CH_{3}CH(Cl)CH_{2}COOH < ClCH_{2}CH_{2}CH_{2}COOH$
D) $CH_{3}CH_{2}CH(Cl)COOH < CH_{3}CH(Cl)CH_{2}COOH > ClCH_{2}CH_{2}CH_{2}COOH$
Explanation
The correct answer is Option A: $CH_{3}CH_{2}CH(Cl)COOH > CH_{3}CH(Cl)CH_{2}COOH > ClCH_{2}CH_{2}CH_{2}COOH$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.