Q. If the radius of $K^{+}$ and $F^{-}$ are 133 pm and 136 pm respectively, the distance between $K^{+}$ and $F^{-}$ in KF is
A) 269 pm
B) 134.5 pm
C) 136 pm
D) 3 pm
Explanation
(a)
Distance between $K^{+}$ and $F^{-}$ in KF
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = r_{K^{+}} + r_{F^{-}} = 133 + 136 = 269\ pm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.