(b) In fcc unit cell $\ \ \ \ \ \sqrt{2a} = 4r\ \ \ \ \Rightarrow r = \frac{\sqrt{2}\ a}{4}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{\sqrt{2} \times 361}{4} = 127\ pm$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.