(d)
Volume of an atom $= \frac{4}{3}\pi r^{3}$
In fcc, number of atoms per unit cell = 4
$\therefore$ Volume of total atoms $= 4 \times \frac{4}{3}\ \pi r^{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{16}{3}\pi r^{2}$