Q. The normality of 10% (weight/volume) acetic acid is

A) 1 N
B) 1.3 N
C) 1.7 N
D) 1.9 N
Explanation

(c)
$N = \frac{w \times 1000}{eq.\ wt.\ \times V(mL)}$
$= \frac{10 \times 1000}{60 \times 100} = 1.66\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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