Q. A solution of 4.5 g of a pure non-electrolyte in 100 g of water was found to freeze at $0.465℃$ . The molecular weight of the solute closest to ($k_{f} = 1.86$)

A) 135.0
B) 172.0
C) 90.0
D) 180.0
Explanation

(d)
M$= \frac{1000 \times k_{f} \times w}{\mathrm{\Delta}T_{f} \times W}$
$= \frac{1000 \times 1.86 \times 4.5}{0.465 \times 100}\ \$
$\ \ \ \ \ = 180\ g$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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