(a) $N_{1}V_{1} = N_{2}V_{2}$ $36 \times 50 = N_{2} \times 100$ $\therefore N_{2} = \frac{36 \times 50}{100} = 18$ $\because Molarity\ of\ acid = \frac{Normality}{Basicity} = \frac{18}{2} = 9\ M$
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