Q. How many moles of $Al_{2}\ \left( SO_{4}\ \right)_{3}$ would be in 50 g of the substance?
A) 0.083 mol
B) 0.952 mol
C) 0.481 mol
D) 0.140 mol
Explanation
(d)
Moles = $\frac{mass}{molecular\ weight\ }$
Given, mass of $Al_{2}\ ({SO}_{4})_{3}$ = 50 g
molecular mass of $Al_{2}\ ({SO}_{4})_{3}$ = 342
$\therefore$ Moles of $Al_{2}\ ({SO}_{4})_{3}\ = \frac{50}{342} = 0.14$ mol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.