Q. How much of 0.1 M $H_{2}\ {SO}_{4}$ solution is required to neutralise 50 mL of 0.2 M NaOH solution?
A) 50 mL
B) 5.0 mL
C) 0.50 mL
D) 100 mL
Explanation
(a)
For complete neutralisation,
m. wq of $H_{2}{SO}_{4}$ = m. eq. of NaOH
$\ \ \ \ \ \ \ \ \ \ 0.1 \times \ 2 \times \ V = \ 50\ \times 0.2 \times \ 1$
$\ \ \ \ \ \ (\because 0.1M\ H_{2}{SO}_{4} = 0.2N\ H_{2}{SO}_{4})$
V = 50mL
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.