(b) $P_{H_{2}O} =$ $X_{H_{2}O}\ p_{total}\$ $\ \ \ \ \ \ \ \ \ \ = 0.0287 \times 0.977$ =0.028atm $p_{total}\$= $p_{dry\ air} + p_{H_{2}O}\$ $p_{dry\ air} = p_{total} + p_{H_{2}O}$ = 0.977-0.028 =0.949 atm
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Ph.D. in Physics with 19+ years of teaching experience.