Q. A solution contains $1.2046\ \times \ 10^{24}$ hydrochloric acid molecules in 1 ${dm}^{3}$ of the solution. The strength of the solution is
A) 6 N
B) 2 N
C) 4 N
D) 8 N
Explanation
(b)
$6.023\ \times \ 10^{23}$molecules of HCl $\cong$ 1mole HCl
Hence, $1.2046\ {\times \ 10}^{24}$ molecules of
HCl $\cong \frac{1.2046\ {\times \ 10}^{24} \times 1}{6.023\ \times \ 10^{23}}$ $\cong$ 2 moles HCl
Thus, two moles (= two gram-equivalents) of HCl are dissolved in one ${dm}^{3}$(one litre) solution.
Therefore the solution will be 2N.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.