Q. 100 $mL$ of 0.3 $HCl$ is mixed with 200 mL of $0.6\ N$ $H_{2}SO_{4}$. The final normality of the resulting solution will be
A) 0.3 N
B) 0.2 N
C) 0.5 N
D) 0.1 N
Explanation
(c)
$N_{1}V_{1} + N_{2}V_{2} = N_{3}V_{3}$
$0.3 \times 100 + 0.6 \times 200 = N_{3} \times 300$
$0.3 + 1.2 = 3N_{3}$
$N_{3} = 0.5$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.