Q. The volume of water to added to $100\ {cm}^{3}$ of 0.5 N $H_{2}{SO}_{4}$ to get decinormal concentration is
A) $400\ {cm}^{3}$
B) $450\ {cm}^{3}$
C) $500\ {cm}^{3}$
D) $100{\ cm}^{3}$
Explanation
(a)
${\ \ \ \ \ \ \ \ \ \ N}_{1}V_{1}\ \ \ \ = \ \ \ \ N_{2}V_{2}$
$\ \ \ 0.5\ \times \ 100 = \ 0.1 \times V_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V_{2}\ = \ 500\ cm^{3}$
$\therefore$ Water to be added to $100{\ cm}^{3}$ solution
=500-100= 400$\ {cm}^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.