Q. The weight of $H_{2}C_{2}O_{4} \bullet 2H_{2}O$ required to pressure 500 mL of 0.2 N solution is
A) 63 g
B) 6.3 g
C) 0.63 g
D) 126 g
Explanation
(b)
Eq. wt. of $H_{2}C_{2}O_{4} \bullet 2H_{2}O$
$= \frac{2 + 24 + 64 + 2(2 + 16)}{2}$
$= 63$
$w = \frac{NEV}{1000} = \frac{0.2 \times 63 \times 500}{1000} = 6.3\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.