Q. The amount of ice that will separate out on cooling a solute containing 50 g of ethylene glycol in 200 g water to $- 9.3℃$ will be
A) 8.37 g
B) 161.3 g
C) 3.87 g
D) 38.7 g
Explanation
(d)
$M = \frac{1000 \times k_{f} \times w}{\mathrm{\Delta}T \times W}$
$62 = \frac{1000 \times 1.86 \times 50}{9.3 \times W}$
$W = 161.3\ g$
Total water =200 g
Hence, ice separated$= (200 - 161.3)g = 38.7\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.