Q. The modal elevation constant of water is $0.52℃$. The boiling point of 1.0 modal aqueous KCl solution (assuming complete dissociation of KCl), therefore, should be
A) $98.96℃$
B) $100.52℃$
C) $101.04℃$
D) $107.01℃$
Explanation
(c)
$\mathrm{\Delta}T_{b} = im\ k_{b} = 0.52 \times 1 \times 2 = 1.04$
$\therefore T_{b} = T + \mathrm{\Delta}T_{b} = 100 + 1.04 = 101.04℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.