Q. The molarity of the solution obtained by dissolving 2.5g of NaCl in 100 mL of water is
A) 0.00428 moles
B) 428 moles
C) 0.428 moles
D) 0.0428 moles
Explanation
(c)
Molarity (M)
= $\frac{weight\ of\ solute\ }{mol.wt.of\ solute\ \times \ \ volume\ of\ the\ solution\ } \times 1000\$
$= \frac{2.5\ \times \ 1000}{58.5\ \times \ 100}$ = 0.428 mol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.