Q. A molar solution of $NaCl$ has a density of $1.21\ g\ mL^{- 1}$. The molarity of this solution is
A) 2.35
B) 1.143
C) 2.95
D) 1.356
Explanation
(b)
$M = \frac{m \times d}{1 + \frac{mM_{2}}{1000}} = \frac{1 \times 1.21}{1 + \frac{1 \times 58.5}{1000}}$
$= \frac{1.21 \times 1000}{1000 + 58.5}$
$= 1.143\ M$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.