Q. Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is
A) 9 L
B) 1.8 L
C) 8 L
D) 0.9 L
Explanation
(d)
$\because\$20 g glucose is dissolved in 100 mL solution
$\therefore$ 1 g glucose is dissolved in =$\frac{100}{20}$
180 g (g-mole) glucose is dissolved in
= $\frac{100\ \times \ 180}{20}$= 900 mL
= 0.9L
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.