The osmotic pressure (At$27℃$) of an aqueous solution (200 mL) containing 6 g of a protein is $2 imes \ 10^{- 3}atm\ .$ If R=0.080 L atm $mol^{- 1}\ K^{- 1}$, the molecular weight of protein is

Question

The osmotic pressure (At$27℃$) of an aqueous solution (200 mL) containing 6 g of a protein is $2 	imes \ 10^{- 3}atm\ .$ If R=0.080 L atm $mol^{- 1}\ K^{- 1}$, the molecular weight of protein is

Dr. Abubacker · Accepted Answer

(b)
$\pi V = \ \frac{w}{m}\ RT\$
M=$\frac{wRT}{\pi V}\$
Here, w=6 g$,\ \ \pi\  = \ 2 	imes 10^{- 3}\ atm,$ T=300 K,
R=0.080 L-atm mo$l^{- 1}\ K^{- 1},$ V =200 mL =0.2 L
M$= \frac{6\  	imes 0.080 	imes 300}{2 	imes 10^{- 3} 	imes 0.2} = 3.6 	imes 10^{5}\ \ \$

Q. The osmotic pressure (At$27℃$) of an aqueous solution (200 mL) containing 6 g of a protein is $2 \times \ 10^{- 3}atm\ .$ If R=0.080 L atm $mol^{- 1}\ K^{- 1}$, the molecular weight of protein is

Explanation

Reviewed by Dr. Abubacker

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