(a) Given, m=0.2 $k_{f} = 1.85\ \ \ \$ $\alpha = 0.3\ \$ $\therefore$ i=1+$\alpha$=1.3 $\mathrm{\Delta}T_{f} = molality\ \times k_{f} \times i$ =0.2$\times 1.85 \times 1.3$ =0.481${^\circ}$ $\therefore$ freezing point =-0.481$℃$
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