(b)
Normality of the mixed solution
= $\frac{N_{1}V_{1} + N_{2}V_{2}\ }{V_{1} + V_{2}}$
= $\frac{0.6 \times \frac{100}{1000} + 0.3 \times \frac{200}{1000}}{\frac{100 + 200}{1000}}$
=$\frac{0.6 \times 0.1 + 0.3 \times 0.2}{0.3}$
=$\frac{0.06 + 0.06}{0.3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{0.12}{0.3}$ =0.4 N