20 g of binary electrolyte (mol. wt. =100) are dissolved in 500 g of water. The depression in freezing point of the solution is $0.74℃$ ($k_{f} = 1.86\ Km^{- 1})$ the degree of ionisation of the electrolyte is

Question

Dr. Abubacker · Accepted Answer

(a)
$\mathrm{\Delta}T = \frac{1000 	imes k_{f} 	imes w}{m 	imes 500}$
0.74=$\frac{1000 	imes 1.86 	imes 20}{m 	imes 500}$
m=100
Actual molecular mass =100
$	herefore$ The degree of ionisation of the electrolyte is 0% .

Q. 20 g of binary electrolyte (mol. wt. =100) are dissolved in 500 g of water. The depression in freezing point of the solution is $0.74℃$ ($k_{f} = 1.86\ Km^{- 1})$ the degree of ionisation of the electrolyte is

Explanation

Reviewed by Dr. Abubacker

Want more practice?