Q. If 20 mL of 0.4 N $NaOH$ solution completely neutralizes 40 mL of a dibasic acid, the molarity of the acid solution is
A) 0.1 M
B) 0.3 M
C) 0.5 M
D) 0.7 M
Explanation
(a)
$20 \times 0.4 = 40 \times N\ \ (\because N_{1}V_{1} = N_{2}V_{2})$
or $N = 0.2$
$\therefore M = \frac{0.2}{2} = 0.1\ M$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.