Q. Molarity of a solution prepared by dissolving 75.5 g of pure KOH in 540 mL solution is
A) 1.50 M
B) 2.50 M
C) 3.50 M
D) 5.01 M
Explanation
(b)
$M = \frac{w \times 1000}{m \times V(mL)} = \frac{75.5 \times 1000}{56 \times 540} = 2.50\ M$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.