Q. Which of the following solutions has the highest normality?
A) 6 g of $NaOH$/100 $mL$
B) $0.5\ M\ H_{2}SO_{4}$
C) N phosphoric acid
D) 8 g of KOH/L
Explanation
(a)
$N = \frac{6 \times 1000}{40 \times 100} = 1.5\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.