(c)
$\pi V = \frac{W}{m}\ RT$
for isotonic solutions, osmotic pressure ($\pi$) is same
$\frac{W_{1}}{m_{1}V_{1}} = \frac{W_{2}}{m_{2}V_{2}}\ \$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V_{1} = 1L,\ V_{2} = 100\ mL = 0.1L\$
$\frac{W_{1}}{60 \times 1} = \frac{10}{342 \times 0.1}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ W_{1} = 17.54\frac{g}{L}$