Explanation

(d)
Normality = $\frac{no.of\ g - equivalents\ of\ solute\ }{volume\ of\ solution\ in\ litre\ \ }$
Given, basicity = 2, mol. wt. = 200,
V = 100 mL = 100/1000L
Normality = 0.1
Eq. wt. = $\frac{mole.wt.\ }{basicity\ } = \frac{200}{2}\$= 100
N= $\frac{mass\ /eq.\ \ wt.\ }{volume\ of\ solution\ in\ litre\ }$
or 0.1 =$\frac{mass\ /100}{100/1000}$
or 0.1 = $\frac{mass\ /100}{0.1}$
or mass = 0.1 $\times$ 0.1$\times$ 100= 1.0 g