Q. The freezing point of equimolal aqueous solution will be highest for
A) $C_{6}H_{5}NH_{3}Cl\$
B) $La(NO_{3})_{3}$
C) $C_{6}H_{12}O_{6}\$
D) $Ca(NO_{3})_{2}$
Explanation
(c)
Glucose ($C_{6}H_{12}O_{6}\$ ) is a non-electrolyte, hence i=1, while others are electrolyte, hence i > 1.
$\therefore$ $\mathrm{\Delta}T_{f} = i \times k_{f} \times molality$
The value of $\mathrm{\Delta}T_{f}$ is lowest for glucose, hence its freezing point is maximum.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.