Q. An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is
A) 0.01
B) 0.02
C) 1
D) 20
Explanation
(b)
$\frac{p^{0} - p_{s}}{p^{0}} = \frac{w}{m} \times \frac{M}{W} = \frac{18}{180} \times \frac{18}{90} = 0.02$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.