Q. The vant’s Hoff factor for 0.1 M $Ba\left( NO_{3} \right)_{2}$ solution is 2.74. The degree of dissociation is
A) 91.3%
B) 87%
C) 100%
D) 74%
Explanation
(b)
$Ba\left( NO_{3} \right)_{2} \rightleftharpoons Ba^{2 +} + 2NO_{3}^{-}$
1 mole 0 0 initial
$1 - \alpha\ \ \ \ \ \ \ \ \ \ \ \ \ \ \alpha\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2\alpha$after dissociation
Total moles$\ = 1 + 2\alpha$
$i = 1 + 2$α
$\alpha = \frac{i - 1}{2} = \frac{2.74 - 1}{2} = 0.87 = 87\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.