Q. At temperature $327℃$ and concentration C osmotic pressure of a solution is p, the same solutions at concentration C/2 and a temperature $427℃\$shows osmotic pressure 2 atm, value of p will be
A) $\frac{12}{7}$
B) $\frac{24}{7}$
C) $\frac{6}{5}$
D) $\frac{5}{6}$
Explanation
(b)
$\pi V = nRT$ $\ \ \$
$\ \pi = \frac{n}{V}RT$
$\pi = CRT$
$\frac{\pi_{1}}{\pi_{2}} = \frac{C_{1}RT_{1}}{C_{2}RT_{2}}$
$\pi_{1} = p,\ \pi_{2} = 2atm\ C_{1} = C,\ \ C_{2} = \frac{C}{2}$
$T_{1}$=600 K, ${\ \ \ \ \ T}_{2}\$= 700 K
$\frac{P}{2} = \frac{2 \times C \times R \times 600}{C \times R \times 700}$
p=$\frac{24}{7}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.