Q. $6.02 \times 10^{20}$molecules of urea are present in 100 mL of its solution. The concentration of urea solution is
A) 0.1 M
B) 0.01 M
C) 0.001 M
D) 0.02 M
Explanation
(b)
Mole of urea $= \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} = 10^{- 3}$mol
Conc. of solution (in molarity)$= \frac{10^{- 3}}{100} \times 1000 = 0.01\ M$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.