Q. Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is
A) 23.077%
B) 230.77%
C) 2.3077%
D) 0.23077%
Explanation
(a)
If $H_{2}O$ = x mol = 18x g
Then urea = x mol = 60x g
Total mass of the solution
=18x + 60x=78xg
Mass % of urea = $\frac{18x}{78x} \times$100
=23.077%
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.