Vapour pressure of$\ CCl_{4}\$at $25℃$ is 143 mm of Hg and 0.5 g of a non-volatile solute (mol. wt=65) is dissolved in$100$ $mL\ CCl_{4}$. Find the vapour pressure of the solution. (Density of $CCl_{4} = 1.58\ g/cm^{2}$)

Question

Dr. Abubacker · Accepted Answer

(b)
$\frac{p^{0} - p_{s}}{p^{0}} = \frac{w 	imes M}{m 	imes W}$
$\frac{143 - p_{s}}{143} = \frac{0.5}{65} 	imes \frac{154}{1.58 	imes 100}$
[$\because$ molecular weight of $CCl_{4} = 154$ and weight=density$	imes$volume]
$143 - p_{s} = 1.07\  \Rightarrow p_{s} = 141.93\ mm$

Q. Vapour pressure of$\ CCl_{4}\$at $25℃$ is 143 mm of Hg and 0.5 g of a non-volatile solute (mol. wt=65) is dissolved in$100$ $mL\ CCl_{4}$. Find the vapour pressure of the solution. (Density of $CCl_{4} = 1.58\ g/cm^{2}$)

Explanation

Reviewed by Dr. Abubacker

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