Q. When $X$ amperes of current is passed through molten ${AlCl}_{3}$ for 96.5 s. 0.09 g of aluminium is deposited. What is the value of X?
A) 10 A
B) 20 A
C) 30 A
D) 40 A
Explanation
(a)
Current $i\ = ?$
Equivalent weight of $Al\ = \frac{27}{3}\ = 9$
$w = Z.i.t\ \ or\ \ i = \frac{w}{Z.t}\ = \ \frac{0.09\ \times 96500}{9\ \times 96.5}$
= 10 A
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.