Q. What is the cell reaction occurring in Daniel cell (Galvanic cell)?
A) $Cu(s)\ + \ {ZnSO}_{4}(aq)\ \longrightarrow \ {CuSO}_{4}(aq)\ + \ Zn(s)$
B) $Zn(s)\ + \ {CuSO}_{4}(aq)\ \rightarrow \ Cu(s)\ + \ {ZnSO}_{4}(aq)$
C) $Ni(s)\ + \ {ZnSO}_{4}(aq)\ \longrightarrow \ Ni{SO}_{4}(aq)\ + \ Zn(s)$
D) $2Na(s)\ + \ Cd{SO}_{4}(aq)\ \longrightarrow \ {Na}_{2}{SO}_{4}(aq)\ + \ Cd\ (s)$
Explanation
(b)
In Galvanic cell (Daniel cell) the electrical energy is produced from chemical reactions.
At anode Zn → ${Zn}^{2 +} + \ {2e}^{-}$ (oxidation)
At cathode ${Cu}^{2 +} + \ {2e}^{-}\ \longrightarrow Cu$ (reduction)
Cell reaction Zn + ${Cu}^{2 +}$ $\longrightarrow$ ${Zn}^{2 +}$ + Cu
Or Zn(s) + ${CuSO}_{4}(aq)$ → Cu(s) + ${ZnSO}_{4}(aq)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.