Q. The reduction electrode potential, E of 0.1 M solution of $M^{+}$ ions $(E_{RP}\ \ = \ - 2.36\ V)$ is
A) -4.82 V
B) -2.41 V
C) +2.41 V
D) None of these
Explanation
(b)
$E\ = \ E_{RP}^{{^\circ}}\ + \ \frac{0.0591}{n}\log{\lbrack M^{+}\rbrack}$
Given,
$E_{RP}^{{^\circ}}\ = \ - \ 2.36\ V,\ \lbrack M^{+}\rbrack\ = \ 0.1\ M$
$\ \ \ n\ = \ 1\ (for\ M^{+}\ \rightarrow \ M\ )$
$E\ = \ E_{RP}^{{^\circ}}\ + \ \frac{0.0591}{n}\log{\lbrack M^{+}\rbrack}$
$\ = \ - 2.36\ + \ \frac{0.0591}{1}\log{0.1}$
$= \ - \ 2.36\ + \ 0.0591\ \times \ ( - 1)$
$\ \ \ \ \ \ = \ - \ 2.36\ –\ 0.0591$
$= \ - \ 2.419\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.