Q. The specific conductance of 0.1 N $KCl$ solution at $23℃$ is $0.012\ {ohm}^{- 1}\ {cm}^{- 1}.$ The resistance of cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be
A) $0.66\ {cm}^{- 1}$
B) $1.12\ {cm}^{- 1}$
C) $0.918\ {cm}^{- 1}$
D) $1.66\ {cm}^{- 1}$
Explanation
(a)
$\kappa = \frac{1}{R}\ \times$cell constant
$\therefore\$Cell constant$= \kappa \times R = 0.012 \times 55 = 0.66\ {cm}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.