Q. 9.65 C electric current is passed through fused anhydrous $MgCl_{2}.$ The magnesium metal thus obtained is completely converted into a Grignard reagent. The number of moles of Grignard reagent obtained is
A) $5 \times 10^{- 4}$
B) ${1 \times 10}^{- 4}$
C) ${5 \times 10}^{- 5}$
D) ${1 \times 10}^{- 5}$
Explanation
(c)
96500 C current produces 12 g Mg
9.65 C current produces
$= \ \frac{12\ \times 9.65}{96500}\ = \ 1.2\ \times \ 10^{- 3}g\ Mg\$
$= \ \frac{1.2\ \times \ 10^{- 3}}{24}\ = \ 5\ \times \ 10^{- 5}\ mol\ Mg$
$R\ —\ X\ + \ Mg\ \longrightarrow \ \ \ RMg\ X$ Grignard reagent
$\ \ \ \ \ \ 5\ \times \ 10^{- 5}\ \ \ \ \ \ \ \ \ \ \ \ \ 5\ \times \ 10^{- 5}\ \$
Mol mol
Hence, number of moles of $RMgX$ produced $= \ {5\ \times 10}^{- 5}\ .$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.