Q. How long (in hours) must a current of 5.0 A be maintained to electroplate 60 g of calcium from molten ${CaCl}_{2}$?

A) 27 h
B) 8.3 h
C) 11 h
D) 16 h
Explanation

(d)
$w\ = 60\ g$
$i\ = \ 5A$
Equivalent weight of $Ca\ = \ \frac{atomic\ weight}{valency}\$
$= \ \frac{40}{2} = 20$
According to first law of Faraday electrolysis
$w\ = \ Zit\ = \ \frac{equivalent\ weight}{96500}\ \times i\ \times t$
$\therefore\ 60\ = \ \frac{20}{96500}\ \times 5\ \times t$
$t\ = \ \frac{96500\ \times 60}{20\ \times 5}\ s$
$= \ \frac{96500\ \times 60}{20\ \times 5\ \times 60\ \times 60}h$
= 16.08 h

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.